java - how should i make my switch go back to main switch? -

good day... creating address book program... used switch in main menu... , planning create switch edit menu... problem is.. don't know how go main switch... main program:

import javax.swing.joptionpane; import javax.swing.jtextarea;  public class addressbook {      private addressbookentry entry[];     private int counter;      public static void main(string[] args) {         addressbook = new addressbook();         a.entry = new addressbookentry[100];         int option = 0;         while (option != 6) {             string content = "choose option\n\n"                     + "[1] add entry\n"                     + "[2] delete entry\n"                     + "[3] update entry\n"                     + "[4] view entries\n"                     + "[5] view specific entry\n"                     + "[6] exit";             option = integer.parseint(joptionpane.showinputdialog(content));             switch (option) {                 case 1:                     a.addentry();                     break;                 case 2:                      break;                 case 3:                     a.editmenu();                     break;                 case 4:                     a.viewall();                     break;                 case 5:                     break;                 case 6:                     system.exit(1);                     break;                 default:                     joptionpane.showmessagedialog(null, "invalid choice!");             }         }     }      public void addentry() {         entry[counter] = new addressbookentry();         entry[counter].setname(joptionpane.showinputdialog("enter name: "));         entry[counter].setadd(joptionpane.showinputdialog("enter add: "));         entry[counter].setphoneno(joptionpane.showinputdialog("enter phone no.: "));         entry[counter].setemail(joptionpane.showinputdialog("enter e-mail: "));         counter++;     }      public void viewall() {         int = 0;         (; < counter; i++) {             joptionpane.showmessagedialog(null, new jtextarea(entry[i].getinfo()));         }     }      public void editmenu() {         int option = 0;         while (option != 6) {             string content = "choose option\n\n"                     + "[1] edit name\n"                     + "[2] edit address\n"                     + "[3] edit phone no.\n"                     + "[4] edit e-mail address\n"                     + "[5] go main menu\n";             option = integer.parseint(joptionpane.showinputdialog(content));             switch (option) {                 case 1:                     editentry();                     break;                 case 2:                     break;                 case 3:                     break;                 case 4:                     break;                 case 5:                     break;                 default:                     joptionpane.showmessagedialog(null, "invalid choice!");             }         }     }      public void editentry() {         string ename;         ename = joptionpane.showinputdialog("enter name edit: ");         (int = 0; < counter; i++) {             if (entry[i].getname().equals(ename)) {                 entry[i].setname(joptionpane.showinputdialog("enter new name: "));             }         }     } } 

please help... in advance :)

to return caller, can use return; instead of break;

in editmenu

            case 5:                 return; 

however, suspect problem that

while (option != 6) { 

should be

while (option != 5) { 

you use label break out of while loop same thing here.