global variables - Python: how to create a function pointer with a set argument? -

my problem:

given following:

def foo(a,b) 

i trying call python 'map' function while passing in list 'a' use set value 'b.'

another relevant fact 'b' user input , thus, cannot use syntax:

def foo(a,b='default value') 

i want 'map' call this:

map(foo_wrapper,list_for_a) 

where 'foo_wrapper' function takes in 'a' uses user specified 'b.'

i don't know whether function pointers can specified way , suspect cannot.

my solution problem uses globals, if there's more elegant way , above impossible, mark answer well.

here solution in nutshell:

b = '' def foo(a,b):   print b,a  def foo_wrapper(a):   foo(a,b)  def main():   if sys.argv[1]:     = ['john', 'jacob', 'jingle way']     global b     b = sys.argv[1]     map(foo_wrapper,a) 

there may typo or 2 in above; simplifying problem need do.

thanks replies!

you can use functools.partial() purpose:

from functools import partial  def f(a, b):     return + b  x = range(10) print map(partial(f, b=3), x) 

prints

[3, 4, 5, 6, 7, 8, 9, 10, 11, 12]