c# 4.0 - How to Implicitly Convert an Enumerable of a type with Implicit Conversion Operators in C# 4.0 -

given:

public struct id {     readonly int m_id;      public id(int id)     { m_id = id; }      public static implicit operator int(id id)     { return id.m_id; }      public static implicit operator id(int id)     { return new id(id); } } 

can implicitly convert

ienumerable<int> 

to

ienumerable<id> 

and vice versa. in way. note

var ids = new int[]{ 1, 2 }; ids.cast<id>(); 

does not appear work , covariance not appear working in case, either. of course, doing select work i.e.:

ids.select(id => new id(id)); 

but looking make work implicitly, writing:

ienumerable<id> ids = new int[]{ 1, 2 }; 

and yes, know can written as:

ienumerable<id> ids = new id[]{ 1, 2 }; 

but issue in cases enumerable of ints comes different source, such file example.

i sorry if there answer this, not find it.

according this answer want not possible. can close not implicitly casting id collection. :

public class ids : list<int> {     public static implicit operator ids(int[] intarray)     {         var result = new ids();         result.addrange(intarray);         return result;     } } 

then possible :

ids t = new [] { 3,4 };